8y^2+48y+72=0

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Solution for 8y^2+48y+72=0 equation: 



8y^2+48y+72=0

a = 8; b = 48; c = +72;
Δ = b2-4ac
Δ = 482-4·8·72
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-48}{16}=-3$

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